Dr.Stat

Nee, dat klopt niet. We zullen je op weg helpen. ${\overline{X}}_3=\frac{4+4+7}{3}=\frac{15}{3}=5$. ${\mathrm{KS}}_{t\mathrm{,3}}=n_j\times ({\overline{X}}_3-\overline{X}{)}^2=(5-4{)}^2=3\times (1{)}^2=3$. ${\mathrm{KS}}_t={\mathrm{KS}}_{t\mathrm{,1}}+{\mathrm{KS}}_{t\mathrm{,2}}+{\mathrm{KS}}_{t\mathrm{,3}}$.

Nee, dat is niet goed. We zullen je op weg helpen. ${\overline{X}}_3=\frac{4+4+7}{3}=\frac{15}{3}=5$. ${\mathrm{KS}}_{t\mathrm{,3}}=n_j\times ({\overline{X}}_3-\overline{X}{)}^2=(5-4{)}^2=3\times (1{)}^2=3$. ${\mathrm{KS}}_t={\mathrm{KS}}_{t\mathrm{,1}}+{\mathrm{KS}}_{t\mathrm{,2}}+{\mathrm{KS}}_{t\mathrm{,3}}$.

Nee, dat klopt niet. We zullen je op weg helpen. ${\overline{X}}_3=\frac{4+4+7}{3}=\frac{15}{3}=5$. ${\mathrm{KS}}_{t\mathrm{,3}}=n_j\times ({\overline{X}}_3-\overline{X}{)}^2=(5-4{)}^2=3\times (1{)}^2=3$. ${\mathrm{KS}}_t={\mathrm{KS}}_{t\mathrm{,1}}+{\mathrm{KS}}_{t\mathrm{,2}}+{\mathrm{KS}}_{t\mathrm{,3}}$.